corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

which is not an improper fraction equal to 8?

is 3/4 less than or greater than 8/12

What can government do to reduce unemployment?

Miguel's teacher asks him to color 4/8 of his grid. He must use 3 colors; red, blue, green. There must be more green sections than red sections. How can Mig

What does 12(2x3-.5)+10

Thomas has a box with four black color bottles and eight gray color bottles. Two bottles are drawn without replacement from the box. What is the probability tha

A board is cut into 10 equal pieces.how many pieces together represent 3/5 of the board?explain how you arrived at your answer.

what do b times h mean

How do you express 4 feet 9 inches into height in feet only using a mixed number?

The relationships of plants and animals to each other and their environment is what ecologists call _____.