missredhead9911 missredhead9911

03-06-2019
Mathematics

contestada

The circle below is centered at (-1, 1) and has a radius of 3. What is its
equation?

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jdoe0001 jdoe0001

03-06-2019

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-1}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[2em] [x-(-1)]^2+[y-1]^2=3^2\implies (x+1)^2+(y-1)^2=9[/tex]

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