gabby15222 gabby15222
  • 01-11-2020
  • Mathematics
contestada

Find all the solution of the equation in the interval [0,2pi] 2sin2x =0

Respuesta :

naenaecvsh naenaecvsh
  • 01-11-2020

Answer:

π

8

and

9

π

8

Step-by-step explanation:2

sin

(

2

x

)

−

√

2

=

0

sin

2

x

=

√

2

2

2

x

=

sin

−

1

(

sin

2

x

)

=

sin

−

1

(

√

2

2

)

=

π

4

2

x

=

π

4

⇒

x

=

π

8

−

π

8

=

π

+

π

8

=

9

π

8

For:

888

0

<

x

≤

π

π

8

and

9

π

8

Answer Link
gufeliz1965
gufeliz1965 gufeliz1965
  • 01-11-2020

See attachment for math work and answer.

Ver imagen gufeliz1965
Answer Link

Otras preguntas

What does EDI stand for?
Why do you need two ammonium ions and one sulfide ion for the formula for ammonium sulfide?
What event in europe in 1814 allowed the british to concentrate all their forces in america?
Which of the following is a composite number that is divisible by both 3 and 5?A.116B.135C.1025D.1546
What is it mean by the world is bigger than 94 by 50 feet
If an element has 3 valence electrons, how many dots will be in the elements dot diagram?
Solve the following equation by completing the square: x^4 – 4x^2 + 2 = 0 Please show steps, and if you can, leave the numbers as fractions and sqrts instead
Lonnie ordered 12$ copies of the same book.h3 books cost 19$ each and the order has a 15$ charge.what is the total cost of Lonnie's order?
What organelles converts light energy into food?
If a penny is tossed three times and comes up heads all three times, the probability of heads on the fourth trial is ___.