Respuesta :

mariangel
Let's consider a, a+1 and a+2 the three consecutives integers

a+(a+1)+(a+2)=171

3a+3=171
3a=171-3
3a=168
a=56

So the numbers are: 56, 57, 58.

Check: 56+57+58=171
tylermiller5354

Answer:

56,57,58

Step-by-step explanation:

a+(a+1)+(a+2)=171

3a+3=171

3a=171-3

3a=168

a=56

So the numbers are: 56, 57, 58.

Check: 56+57+58=171